bruceg113...@gmail.com writes: > Lets say I have the following tuple like string. > (128, 020, 008, 255) > > What is the best way to to remove leading zeroes and end up with the > following. > (128, 20, 8, 255) -- I do not care about spaces
You could use a regexp: import re ... re.sub(r"(?<![0-9])0+(?=[0-9])", "", "(128, 020, 008, 255)") I post this because I think it works (interesting corner cases are 10005 and 000), but I don't think, having done it, that it's the right way to go. It's a little too mysterious and fragile. This may be better: re.sub(r"[0-9]+", lambda m: str(int(m.group(0))), "(128, 020, 008, 255)") Obviously, name the function if you prefer (or if you use this in several places) and compile the pattern if you do a lot of these matches. -- Ben. -- https://mail.python.org/mailman/listinfo/python-list
