On 2018-05-20 14:54, bruceg113...@gmail.com wrote:
Lets say I have the following tuple like string.
(128, 020, 008, 255)
What is the best way to to remove leading zeroes and end up with the following.
(128, 20, 8, 255) -- I do not care about spaces
I'd use a few regular expressions:
>>> from re import sub
>>> tuple = '(0128, 020, 008,012, 255)'
>>> sub( " 0*", " ", tuple ) # leading zeroes following space(s)
'(0128, 20, 8,012, 255)'
>>> sub( ",0*", ",", tuple ) # leading zeroes following comma
'(0128, 020, 008,12, 255)'
>>> sub( "\(0*", "(", tuple ) # leading zeroes after opening parend
'(128, 020, 008,012, 255)'
Each step could be written as "tuple = sub( ..."
>>> tuple = sub( " 0*", " ", tuple ) # following space(s)
>>> tuple = sub( ",0*", ",", tuple ) # following comma
>>> tuple = sub( "\(0*", "(", tuple ) # after opening parend
>>> tuple
'(128, 20, 8,12, 255)'
>>>
Or, if you like to make your code hard to read and maintain, you could
combine them all into a single expression:
>>> sub( " 0*", " ", sub( ",0*", ",", sub( "\(0*", "(", tuple ) ) )
'(128, 20, 8,12, 255)'
>>>
--
Michael F. Stemper
What happens if you play John Cage's "4'33" at a slower tempo?
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