On Mon, Feb 5, 2018 at 10:13 AM, <darkorbitaknaen...@centrum.cz> wrote:
> > Hi, I have a problem in continuing the function. > > I'm a beginner, I'm learning from a textbook. I'm going to put the > following examples from a textbook that displays "wrong syntax" > > >> for letter in "ABCDEFGHIJKLMNOPQRSTUVWXYZ": >>>> >>> if letter in "AEIOU": > print(letter, "is a vowel") > else: > print(letter, "is a consonant") > > In this text, I will write a "wrong syntax" after confirming the "else" > function. How is it possible? Using the Bad Version of Python? Please, > please, thank you very much! > > The same error is in the "break" function: > > >> while True: >>>> >>> item = get_next_item() > if not item: > break > process_item(item) > > Here 'wrong syntax' occurs after the "break". > > How is it possible? Bad version of Python? Which version to use? > > Thank you for any advice and help! > > > Check that the code is properly indented. I did a cut/paste and then manually indented the first example and it works fine. -- **** Listen to my FREE CD at http://www.mellowood.ca/music/cedars **** Bob van der Poel ** Wynndel, British Columbia, CANADA ** EMAIL: b...@mellowood.ca WWW: http://www.mellowood.ca -- https://mail.python.org/mailman/listinfo/python-list
