On Mon, Feb 5, 2018 at 10:13 AM, <darkorbitaknaen...@centrum.cz> wrote: > > Hi, I have a problem in continuing the function. > > I'm a beginner, I'm learning from a textbook. I'm going to put the following > examples from a textbook that displays "wrong syntax"
It would be very helpful if you would copy/paste the exact error message instead of just paraphasing it. > >>>> >>>> for letter in "ABCDEFGHIJKLMNOPQRSTUVWXYZ": > > if letter in "AEIOU": > print(letter, "is a vowel") > else: > print(letter, "is a consonant") > > In this text, I will write a "wrong syntax" after confirming the "else" > function. How is it possible? Using the Bad Version of Python? Please, > please, thank you very much! Copying this into either Python 2.7 or 3.5, I get IndentationError (because the indentation of the if and the else is inconsistent), not SyntaxError. I don't know whether that's what you're seeing or if it was just a copying error when you wrote the email. > The same error is in the "break" function: > >>>> >>>> while True: > > item = get_next_item() > if not item: > break > process_item(item) > > Here 'wrong syntax' occurs after the "break". I don't get a syntax error from this at all. I just get NameError because get_next_item is not defined. If it and process_item were both defined, I expect this would run. -- https://mail.python.org/mailman/listinfo/python-list
