On Wednesday, December 6, 2017 at 9:28:26 PM UTC+11, D'Arcy Cain wrote: > On 12/05/2017 07:33 PM, nick.martinez2--- via Python-list wrote: > > I have a question on my homework. My homework is to write a program in > > which the computer simulates the rolling of a die 50 > > times and then prints > > (i). the most frequent side of the die > > (ii). the average die value of all rolls. > > I wrote the program so it says the most frequent number out of all the > > rolls for example (12,4,6,14,10,4) and will print out "14" instead of 4 > > like I need. > > How did you come up with 4? I come up with 3.36 with those numbers. > > > This is what I have so far: > > import random > > > > def rollDie(number): > > rolls = [0] * 6 > > For a small efficiency use "[0] * 7". See below for reason. > > > for i in range(0, number): > > roll=int(random.randint(1,6)) > > rolls[roll - 1] += 1 > > Use "rolls[roll] += 1" here. You save one arithmetic instruction each > time through the loop. Fifty times isn't much saving but imagine fifty > million. > > > return rolls > > return rolls[1:]. No matter how many rolls you only need to do the > slice once. However, you really need a lot of iterations before it > really affects the total run time. > > You need one more thing though. Create a new variable called "total" > and set it to 0.0. Add "total += roll" to your loop. your return > statement is now "return rolls[1:], total/number". > > > > > if __name__ == "__main__": > > result = rollDie(50) > > Now "result, average = ..." > > > print (result) > > print(max(result)) > > This is why you get 14. The maximum number of rolls for any one side is > 14 for side 4. Is that where you got "4"? > > -- > D'Arcy J.M. Cain > Vybe Networks Inc. > http://www.VybeNetworks.com/ > IM:da...@vex.net VoIP: sip:da...@vybenetworks.com
The 'four' is the number which was rolled the highest during the 50 rolls -- https://mail.python.org/mailman/listinfo/python-list
