On 12/05/2017 07:33 PM, nick.martinez2--- via Python-list wrote:
I have a question on my homework. My homework is to write a program in which
the computer simulates the rolling of a die 50
times and then prints
(i). the most frequent side of the die
(ii). the average die value of all rolls.
I wrote the program so it says the most frequent number out of all the rolls for example
(12,4,6,14,10,4) and will print out "14" instead of 4 like I need.
How did you come up with 4? I come up with 3.36 with those numbers.
This is what I have so far:
import random
def rollDie(number):
rolls = [0] * 6
For a small efficiency use "[0] * 7". See below for reason.
for i in range(0, number):
roll=int(random.randint(1,6))
rolls[roll - 1] += 1
Use "rolls[roll] += 1" here. You save one arithmetic instruction each
time through the loop. Fifty times isn't much saving but imagine fifty
million.
return rolls
return rolls[1:]. No matter how many rolls you only need to do the
slice once. However, you really need a lot of iterations before it
really affects the total run time.
You need one more thing though. Create a new variable called "total"
and set it to 0.0. Add "total += roll" to your loop. your return
statement is now "return rolls[1:], total/number".
if __name__ == "__main__":
result = rollDie(50)
Now "result, average = ..."
print (result)
print(max(result))
This is why you get 14. The maximum number of rolls for any one side is
14 for side 4. Is that where you got "4"?
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