On Sat, 11 Feb 2017 06:00 pm, Amit Yaron wrote:
> Another option:
> Use 'float' instead of 'int'. and check using the method 'is_integer'
> of floating point numbers:
>
> >>> 3.5.is_integer()
> False
> >>> 4.0.is_integer()
> True
A bad option...
py> float('12345678901234567')
1.2345678901234568e+16
Notice the last digit of the mantissa?
Beyond a certain value, *all* floats are integer, because floats don't have
enough precision to include a fractional portion.
py> float('12345678901234567.12345').is_integer()
True
The safest way to treat this is to attempt to convert to an int, if that
succeeds return the int; if it fails, try to convert to a float, and if
that succeeds, return the float.
--
Steve
“Cheer up,” they said, “things could be worse.” So I cheered up, and sure
enough, things got worse.
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