Re: Best attack order for groups of numbers trying to destroy each other, given a victory chance for number to number attack.

[skybuck2000]

Hmmm I see that I have made an old mistake of mine ;)

2x2x2x2 is not 8, it's deceptive... it looks like 4x2 = 8 but nope ! :)

This is 2x2=4x2=8x2=16.

and then the next 4 = 16x2 = 32x2 = 64x2 = 128 x 2=256

so it's roughly 24^4 x 256 = 84934656

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