Umar Yusuf wrote:
> Hi all,
> I need your help with any of these questions?
>
> 1-
> http://stackoverflow.com/questions/41083699/python-create-dynamic-loop-based-on-variables-and-csv
You should really make a serious attempt to explain the problem in plain
english. Throwing a piece of code at other people is usually not enough to
get a meaningful answer.
That said, my crystal ball tells me that you want to remove all rows of a
csv before the one containing a keyword in the first column. You can do it
for one keyword/csv-infile/csv-outfile triple,
> with open("keywords.txt", "rb") as keywords, open('folding umbrella-sort-
highest.csv', 'rb') as g, open('lego minecraft-sort-highest.csv', 'rb') as
f, open('filename1.csv', 'wb') as myfile1, open('filename2.csv', 'wb') as
myfile2:
>
> # Step1: Read contents of keywords.tex in variables
> ky = list(keywords.readlines())
> ky1, ky2 = ky[0], ky[1]
>
> # Step2: Read and process folding umbrella-sort-highest.csv
> reader = csv.reader(g)
> umbrella_list = list(reader)
> list1 = filter(lambda e: e[0] in ky1, umbrella_list)
>
> list2 = list(chain(*list1))
> # or better: (available since Python 2.6)
> # print list(chain.from_iterable(list1))
>
> ind_prt1 = umbrella_list.index(list2) +1
> mylist1 = umbrella_list[:ind_prt1]
>
> for r in mylist1:
> wr = csv.writer(myfile1, quoting=csv.QUOTE_ALL)
> wr.writerow(r)
>
and by employing copy-and-paste coding you have managed to do it for two
keywords. Now you want to generalize it for an arbitrary number of triples.
The usual approach is to put the code that works for one instance into a
function and call that for every set of arguments
def process_one(keyword, infile, outfile):
# your code
for keyword, infile, outfile in triples:
process_one(keyword, infile, outfile)
Where can you get those triples? Rather than putting just the keywords into
a text file i would use a csv with three columns:
first_keyword,folding umbrella-sort-highest.csv,filename1.csv
second_keyword,lego minecraft-sort-highest.csv,filename2.csv
...
Then the calling code becomes
with open("keywords.csv", "rb") as f:
for keyword, infile, outfile in csv.reader(f):
process_one(keyword, infile, outfile)
Now to the contents of process_one(). Your code is very complicated. If it
does what I think it can be rewritten as
def process_one(keyword, infile, outfile):
with open(outfile, "wb") as outstream:
writer = csv.writer(outstream, csv.QUOTE_ALL)
with open(infile, "rb") as instream:
for row in csv.reader(instream):
writer.writerow(row)
if row[0] in keyword:
break
By the way, the
row[0] in keyword
test looks odd. Should that be
keyword in row[0]
or
keyword == row[0]
? Without a proper description of the problem that led to your code I have
no way to tell.
> 2-
> http://stackoverflow.com/questions/41081800/python-pandas-how-to-use-dataframe-cell-to-search-another-dataframe-column-and
>
> Thanks in advance for your time.
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