I remembered that I might need to add an else condition if the emp_num
does not exist , so re sending the updated code
def get_unique_number(str(emp_id)):
""" Return the unique number associated with each employee id """
out, err, rc = run("employee_details ls", timeout=600)
emp_unum=""
if rc != 0:
return False
for line in out.split('\n'):
if emp_id in line:
emp_unum = line.split()[0]
else:
print("emp_unum does not exist")
return False
return emp_unum
PS : [Edited the above code with else condition]
Regards,
Ganesh
On Mon, Nov 28, 2016 at 8:38 PM, Ganesh Pal <ganesh1...@gmail.com> wrote:
>
>
> I was trying to write a function that will return me the unique number
> associated with each employee id.The command has the output in the below
> pattern
>
> Linux-Box-1# employee_details ls
> List of names:
> 100910bd9 s7018
> 100d60003 s7019
> 110610bd3 s7020
> 100d60002 s7021
>
>
> Linux-Box-1# employee_details ls | grep "s7020" | awk '{print $1}'
> 100d60003
>
> It's a one liner in Shell :)
>
>
> I tried converting the same in the python style , Any better suggestion
> and loop holes in the below program
>
> def get_unique_number(str(emp_id)):
> """ Return the unique number associated with each employee id """
> out, err, rc = run("employee_details ls", timeout=600)
> emp_unum=""
> if rc != 0:
> return False
>
> for line in out.split('\n'):
> if emp_id in line:
> emp_unum = line.split()[0]
> return emp_unum
>
> I am on Python 2.7 and Linux OS
>
> Regards,
> Ganesh
>
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