On 11/23/2016 11:17 AM, Thomas Grops wrote:
I need a way of generating a random number but there is a catch:
I don't want to include certain numbers, is this possible?
random.randint(1,100) works as it will randomly pick numbers between 1 and 100
but say i don't want 48 to come out is there a way of doing this. It needs to
be an integer too so not a list unless there is a way to convert list to int
Many Thanks Tom
Here's a possible generic approach:
# Come up with a better name for this function
def randx(lo, hi, nw): # nw is a list of not-wanted ints
while True:
n = random.randint(lo, hi)
if n not in nw:
return n
Use it the same way as randint(), plus a list of the not-wanted values.
Short example:
-------
nw = [1, 3, 5, 7, 9] # Odd numbers out
for i in range(10):
print(randx(1, 10, nw), end=' ')
print()
-------
Here's the results I got for 3 runs...
4 4 4 8 10 6 8 2 4 8
8 4 2 4 6 8 2 4 8 8
10 6 6 4 4 4 8 2 8 4
Of course, the not-wanted list can be a single int, or even empty.
--
-=- Larry -=-
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