On Wednesday, 23 November 2016 19:30:21 UTC, Chris Kaynor wrote: > On Wed, Nov 23, 2016 at 11:17 AM, Thomas Grops via Python-list > <python-list@python.org> wrote: > > I need a way of generating a random number but there is a catch: > > > > I don't want to include certain numbers, is this possible? > > > > random.randint(1,100) works as it will randomly pick numbers between 1 and > > 100 but say i don't want 48 to come out is there a way of doing this. It > > needs to be an integer too so not a list unless there is a way to convert > > list to int > > There are a few ways to accomplish this, depending on the exact > requirements. Here are some basic ideas: > - Generate a list of all valid values, and take the one at a random > index. random.sample may be useful. This is guaranteed to complete > (and in only one try), but generally takes extra memory. It is also a > reasonably easy way to sample without replacement (remove the picked > item each time). > - Generate a random number from the larger range, and retry if you get > one in the invalid set. Basically akin to rolling a die, and rerolling > until you don't get a 6. This could theoretically take forever, > however it is often good enough in practice. This will become more and > more inefficient as set of invalid values grows (especially if the > invalid set is a superset of the whole range)
many thanks but am I missing something when I use a list it returns a value with the type list not integer? I need an integer -- https://mail.python.org/mailman/listinfo/python-list
