On 5/2/2016 12:57 PM, Jussi Piitulainen wrote:
DFS writes:
Have: list1 = ['\r\n Item 1 ',' Item 2 ','\r\n ']
Want: list1 = ['Item 1','Item 2']
I wrote this, which works fine, but maybe it can be tidier?
1. list2 = [t.replace("\r\n", "") for t in list1] #remove \r\n
2. list3 = [t.strip(' ') for t in list2] #trim whitespace
3. list1 = filter(None, list3) #remove empty items
After each step:
1. list2 = [' Item 1 ',' Item 2 ',' '] #remove \r\n
2. list3 = ['Item 1','Item 2',''] #trim whitespace
3. list1 = ['Item 1','Item 2'] #remove empty items
Try filter(None, (t.strip() for t in list1)). The default.
Works and drops a line of code. Thx.
Funny-looking data you have.
I know - sadly, it's actual data:
--------------------------------------------------------------------
from lxml import html
import requests
webpage =
"http://www.usdirectory.com/ypr.aspx?fromform=qsearch&qs=TN&wqhqn=2&qc=Nashville&rg=30&qhqn=restaurant&sb=zipdisc&ap=2";
page = requests.get(webpage)
tree = html.fromstring(page.content)
addr1 = tree.xpath('//span[@class="text3"]/text()')
print 'Addresses: ', addr1
--------------------------------------------------------------------
I couldn't figure out a better way to extract it from the HTML (maybe
XML and DOM?)
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