DFS writes: > Have: list1 = ['\r\n Item 1 ',' Item 2 ','\r\n '] > Want: list1 = ['Item 1','Item 2'] > > > I wrote this, which works fine, but maybe it can be tidier? > > 1. list2 = [t.replace("\r\n", "") for t in list1] #remove \r\n > 2. list3 = [t.strip(' ') for t in list2] #trim whitespace > 3. list1 = filter(None, list3) #remove empty items > > After each step: > > 1. list2 = [' Item 1 ',' Item 2 ',' '] #remove \r\n > 2. list3 = ['Item 1','Item 2',''] #trim whitespace > 3. list1 = ['Item 1','Item 2'] #remove empty items
Try filter(None, (t.strip() for t in list1)). The default. Funny-looking data you have. -- https://mail.python.org/mailman/listinfo/python-list