On Sunday, April 3, 2016 at 4:11:49 PM UTC+1, BartC wrote:
> On 03/04/2016 15:41, Loop.IO wrote:
> > On Sunday, April 3, 2016 at 1:12:23 AM UTC+1, BartC wrote:
> >> On 02/04/2016 23:31, Loop.IO wrote:
> >>
> >>> Oh i see, so the code prompts for a name.. so i'm more lost than i
> >>> thought, what do I need to change to make it just create the file with
> >>> the chosen name Launch2.bat without the prompt?
> >>
> >> If you don't want the user to enter anything, then I explained how
> >> before, just use:
> >>
> >> name='C:\\Documents\\PythonCoding\\launch2.bat'
> >>
> >> if that's the file name you need.
> >>
> >> --
> >> Bartc
> >
> > Hi Bartc, i tried that, didn't work
>
> You mean it gave an error when you tried to create that file?
>
> Does that path already exist on your machine? If not then trying to
> create a file in a non-existent path won't work.
>
> You can create the path manually outside of Python. Or look up the docs
> to find out how to do that. A quick google suggested using os.makedirs
> (to create multiple nested paths at the same time).
>
> The following code worked on my machine:
>
> import sys
> import os
>
> def create():
> print("creating new file")
>
> path="c:/Documents/PythonCoding/"
> name=path+"launch2.bat"
>
> try:
> os.stat(path)
> except:
> os.makedirs(path)
>
> print (name)
>
> try:
> file=open(name,'w')
> file.close()
> except:
> print("error occured")
> sys.exit(0)
>
> create()
>
> --
> Bartc
The issue is that it hangs, there is no error. its like it pauses until i press
enter, ill try what you've posted one moment
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