"Martin A. Brown" <mar...@linux-ip.net> a écrit dans le message de
news:mailman.108.1459179618.28225.python-l...@python.org...
Greetings,
In a program "code.py" I read an external file "foo.txt" supposed
to be located in the same directory that "code.py"
python/src/code.py
python/src/foo.txt
In "code.py": f = open('foo.txt', 'r')
But if I run "python code.py" in an other dir than src/ say in
python/, it will not work because file "foo.txt" will be searched
in dir python/ and not in dir python/src/
I think it is possible to build an absolute path for "foo.txt"
using __file__ so that the program works wherever you launch
"python code.py"
Is it the correct way to handle this problem ?
Ayup, I would say so. My suggested technique:
here = os.path.dirname(os.path.abspath(__file__))
foo = os.path.join(here, 'foo.txt')
with open(foo, 'r') as f:
pass
Good luck,
-Martin
--
Martin A. Brown
http://linux-ip.net/
Ok, this is what I intended to do
Thanks for your answer
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