Greetings,
> In a program "code.py" I read an external file "foo.txt" supposed
> to be located in the same directory that "code.py"
>
> python/src/code.py
> python/src/foo.txt
>
> In "code.py": f = open('foo.txt', 'r')
>
> But if I run "python code.py" in an other dir than src/ say in
> python/, it will not work because file "foo.txt" will be searched
> in dir python/ and not in dir python/src/
>
> I think it is possible to build an absolute path for "foo.txt"
> using __file__ so that the program works wherever you launch
> "python code.py"
>
> Is it the correct way to handle this problem ?
Ayup, I would say so. My suggested technique:
here = os.path.dirname(os.path.abspath(__file__))
foo = os.path.join(here, 'foo.txt')
with open(foo, 'r') as f:
pass
Good luck,
-Martin
--
Martin A. Brown
http://linux-ip.net/
--
https://mail.python.org/mailman/listinfo/python-list
