(My first posting seems to got lost)
I want to create a zip file within a Python 2.7 program on windows.
My code:
cmd = ['7za.exe','a','-tzip',archive] + files
status = subprocess.call(cmd)
leads to:
File "fexit.py", line 971, in sendfile_retry
status = subprocess.call(cmd)
File "C:\Python27\lib\subprocess.py", line 522, in call
return Popen(*popenargs, **kwargs).wait()
File "C:\Python27\lib\subprocess.py", line 710, in __init__
errread, errwrite)
File "C:\Python27\lib\subprocess.py", line 958, in _execute_child
startupinfo)
UnicodeEncodeError: 'ascii' codec can't encode character u'\xf6' in position 87:
ordinal not in range(128)
This is because the array "files" contains filenames with non-ASCII
characters.
So, the problem is in subprocess.py, which I cannot modify.
Instead of calling a 7z subprocess with non-ASCII arguments I tried to
call it with a listfile: it starts with a "@" and contains the names of
the files to be packed into the arcive. It is a special 7z feature.
New code:
fileslist = archive + '.list'
flo = open(fileslist,'w')
for file in files: print(file,file=flo)
flo.close()
cmd = ['7za.exe','a','-tzip',archive,'@'+fileslist]
status = subprocess.call(cmd)
But with that I get a new error:
File "fexit.py", line 959, in sendfile_retry
for file in files: print(file,file=flo)
UnicodeEncodeError: 'ascii' codec can't encode character u'\xf6' in position 8:
ordinal not in range(128)
I get the same error message, when i use:
flo = open(fileslist,'wb')
How can I tell open() or print() that I want to write non-ASCII ?
--
Ullrich Horlacher Server und Virtualisierung
Rechenzentrum IZUS/TIK E-Mail: horlac...@tik.uni-stuttgart.de
Universitaet Stuttgart Tel: ++49-711-68565868
Allmandring 30a Fax: ++49-711-682357
70550 Stuttgart (Germany) WWW: http://www.tik.uni-stuttgart.de/
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