On 2015-08-12 06:03, Ltc Hotspot wrote:
Message heard loud and clear:
There are no error messages, the output is the issue.
Question: What sorted function should I write to produce the desired
output, below:
Instead of iterating over "count.items()", iterate over
"sorted(count.items())".
Desired output:
04 3
06 1
07 1
09 2
10 3
11 6
14 1
15 2
16 4
17 2
18 1
19 1
Latest revised code:
count = dict()
fname = raw_input("Enter file name: ")#
handle = open (fname, 'r')#
for line in handle:
if line.startswith("From "):
address = line.split()[5]
line = line.rstrip()
count[address] = count.get(address, 0) + 1
lst = list()
for key,val in count.items():
lst.append( (val, key) )
lst.sort(reverse=True)
for val, key in lst[:12]:
print key,val
[snip]
I don't know why you have a nested 'for' loop; just iterate over the
sorted items and print them. Simple.
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