Cameron Simpson wrote:
> On 26Mar2015 10:03, Peter Otten <__pete...@web.de> wrote:
>>Cameron Simpson wrote:
>>> vars = locals()
>>> varnames = list(vars.keys())
>>
>>That leaves varnames in undefined order. Consider
>>
>>varnames = sorted(vars)
>
> Actually, not necessary.
>
> I started with sorted, but it is irrelevant, so I backed off to "list" to
> avoid introducing an unwarranted implication, in fact precisely the
> implicaion you are making.
>
> The only requirement, which I mentioned, is that the values used to
> initialise the namedtuple are supplied in the same order as the tuple
> field names, so all that is needed is to suck the .keys() out once and use
> them in the same order when we construct the namedtuple. Hence just a
> list.
You are right.
Once I spotted the "error" I failed to notice that you pass the named tuple
as a single argument, i. e. condition(nt), not condition(*nt) :(
By the way, in this case you don't need the list at all:
def vartuple(vars):
return namedtuple("locals", vars)._make(vars.values())
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