On Thu, Feb 19, 2015 at 11:16 AM, Didymus <lynt...@gmail.com> wrote: > On Wednesday, February 18, 2015 at 3:16:40 PM UTC-5, Ian wrote: >> > def perror(self, message, *args, **kws): >> > """ Performance Error Message Level """ >> > # Yes, logger takes its '*args' as 'args'. >> > self._log(PERROR_NUM, message, args, **kws) >> > >> > logging.Logger.perror = perror >> >> I think you need to call self.log, not self._log. The _log method >> appears to assume that the level check has already been performed. You >> really shouldn't be calling it directly anyway, as the leading _ is an >> indication that the method is not part of the public API. > > Yes, I had tried that and get: > > Logged from file log5.py, line 21 > Traceback (most recent call last): > File "/usr/lib64/python2.7/logging/__init__.py", line 851, in emit > msg = self.format(record) > File "/usr/lib64/python2.7/logging/__init__.py", line 724, in format > return fmt.format(record) > File "/usr/lib64/python2.7/logging/__init__.py", line 464, in format > record.message = record.getMessage() > File "/usr/lib64/python2.7/logging/__init__.py", line 328, in getMessage > msg = msg % self.args > TypeError: not all arguments converted during string formatting
log and _log don't have the same function signature. Specifically, log takes *args and _log just takes args (as noted in the comment on the preceding line). -- https://mail.python.org/mailman/listinfo/python-list
