On Wednesday, February 18, 2015 at 3:16:40 PM UTC-5, Ian wrote:
> > def perror(self, message, *args, **kws):
> > """ Performance Error Message Level """
> > # Yes, logger takes its '*args' as 'args'.
> > self._log(PERROR_NUM, message, args, **kws)
> >
> > logging.Logger.perror = perror
>
> I think you need to call self.log, not self._log. The _log method
> appears to assume that the level check has already been performed. You
> really shouldn't be calling it directly anyway, as the leading _ is an
> indication that the method is not part of the public API.
Yes, I had tried that and get:
Logged from file log5.py, line 21
Traceback (most recent call last):
File "/usr/lib64/python2.7/logging/__init__.py", line 851, in emit
msg = self.format(record)
File "/usr/lib64/python2.7/logging/__init__.py", line 724, in format
return fmt.format(record)
File "/usr/lib64/python2.7/logging/__init__.py", line 464, in format
record.message = record.getMessage()
File "/usr/lib64/python2.7/logging/__init__.py", line 328, in getMessage
msg = msg % self.args
TypeError: not all arguments converted during string formatting
I also added:
ll = rootLogger.getEffectiveLevel()
which send back the correct level, but it's still printing out everything...
-Tom
--
https://mail.python.org/mailman/listinfo/python-list
