On Wed, Feb 4, 2015 at 10:19 AM, Joel Goldstick <joel.goldst...@gmail.com>
wrote:
>
>
> On Wed, Feb 4, 2015 at 9:32 AM, Chris Angelico <ros...@gmail.com> wrote:
>
>> On Thu, Feb 5, 2015 at 12:23 AM, Neal Becker <ndbeck...@gmail.com> wrote:
>> > Now I want gen to be a callable that repeats N times. I'm thinking,
>> this
>> > sounds perfect for yield
>> >
>> > class rpt:
>> > def __init__ (self, value, rpt):
>> > self.value = value; self.rpt = rpt
>> > def __call__ (self):
>> > for i in range (self.rpt):
>> > yield self.value
>> >
>> > so I would do:
>> >
>> > my_rpt_obj = obj (rpt ('hello', 5))
>> >
>> > to repeat 'hello' 5 times (for example).
>> >
>> > But this doesn't work. when obj calls self.gen(), that returns a
>> generator, not
>> > the next value.
>> >
>> > How can I make this work? I can't change the interface of the existing
>> class
>> > obj, which expects a callable to get the next value.
>>
>
> Can you actually show your code and the traceback?
>
When you do rpt('hello',5)) you create an instance of rpt but you don't
actually invoke it.
maybe try:
my_rpt_obj = obj(rpt('hello',5))()
If I'm thinking straight, its the final () that actually cause your
__call__ to happen.
>
>> So, if I understand you correctly, you want your rpt object to return
>> 'hello' five times to five consecutive calls?
>>
>> >>> a = rpt()
>> >>> a()
>> 'hello'
>> >>> a()
>> 'hello'
>> >>> a()
>> 'hello'
>> >>> a()
>> 'hello'
>> >>> a()
>> 'hello'
>>
>> You could do that with a generator by repeatedly calling next() on it,
>> or you could just keep track of the number of times you were called:
>>
>> class rpt:
>> def __init__ (self, value, rpt):
>> self.value = value; self.rpt = rpt
>> def __call__ (self):
>> if self.rpt:
>> self.rpt -= 1
>> return self.value
>> # ... otherwise?
>>
>> Up to you to figure out what to do when self.rpt hits zero.
>>
>> ChrisA
>> --
>> https://mail.python.org/mailman/listinfo/python-list
>>
>
>
>
> --
> Joel Goldstick
> http://joelgoldstick.com
>
--
Joel Goldstick
http://joelgoldstick.com
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