On 01/13/2015 02:40 PM, Shambhu Rajak wrote:
I have a string that I get as an output of a command as:

'\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'

I want to fetch ‘*10232ae8944a*’ from the above string.

I want to find a re pattern that could replace all the \x01..\x0z to be
replace by empty string ‘’,  so that I can get the desired portion of string

Can anyone help me with a working regex for it.


Sorry, no regex either, but depending on what exact behavior you need str.isprintable() or even str.isalnum() could be for you:

e.g.

s_in = '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'
s_out = ''.join(c for c in s_in if c.isprintable())

Wolfgang

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