Peter Otten wrote: > Shambhu Rajak wrote: >> I have a string that I get as an output of a command as: >> > '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n' >> >> I want to fetch '10232ae8944a' from the above string. >> >> I want to find a re pattern that could replace all the \x01..\x0z to be >> replace by empty string '', so that I can get the desired portion of >> string >> >> Can anyone help me with a working regex for it. > > I think you want the str.tranlate() method rather than a regex.
Another possibility, but given the length of the list probably not the most efficient one. Aside from re and this one, here is another (tested with Python 3.4.2): filtered = ''.join(filter(lambda ch: ord(ch) > 0x0f, s)) -- PointedEars Twitter: @PointedEars2 Please do not cc me. / Bitte keine Kopien per E-Mail. -- https://mail.python.org/mailman/listinfo/python-list
