bytes/str.ljust()
def pad(b, n=16, c=b"\x0f"):
... length = (len(b)+n-1)//n*n
... return b.ljust(length, c)
Thanks!
One more question. How do I create a single char binary string from a
number? E.g.
>>> bytes([65])
b'A'
It seems to be wrong again. The bytes constructor requires a sequence,
and I don't like creating a list or a tuple just to convert it into a
binary string.
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