Nagy László Zsolt wrote:
> >>> BS = 16
> >>> pad = lambda s: s + (BS - len(s) % BS) * chr(BS - len(s) % BS)
> >>> pad('L')
> 'L\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f'
> >>> pad(b'L')
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> File "<stdin>", line 1, in <lambda>
> TypeError: can't concat bytes to str
>
> How do I write this function so it can pad byte strings? chr(charcode)
> creates a normal string, not a binary string.
>
> I can figure out way for example this:
>
> >>> b'T'+bytearray([32])
>
> but it just don't seem right to create a list, then convert it to a byte
> array and then convert it to a binary string. What am I missing?
You don't need to write your own function, just use the relevant string and
bytes methods. Use the ljust and rjust (left and right justify) methods:
To add padding on the left, justify on the right, and vise versa:
py> "Hello".ljust(20, "\x0f")
'Hello\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f'
py> "Hello".rjust(20, "\x0f")
'\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0fHello'
(The default fill character is space.)
The same works for bytes, except you have to make sure your fill char is
also a byte:
py> b"Hello".rjust(20, b"\x0f")
b'\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0fHello'
py> b"Hello".ljust(20, b"\x0f")
b'Hello\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f\x0f'
--
Steven
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