On 07/22/2014 04:00 PM, fl wrote:
On Tuesday, July 22, 2014 4:35:33 PM UTC-4, Peter Pearson wrote:
On Tue, 22 Jul 2014 12:34:51 -0700 (PDT), fl <r...@gmail.com> wrote:
When you say "def reassign(list)", that means "I'm defining a function
to which the caller will pass one object, and within this function I'm
going to refer to that object by the name 'list'."
Then, when you say "list=[0,1]", that means "Create the object [0,1],
The above is what rebind? see below I cite.
exactly. assigning to a variable within a function makes that variable
local to the function; assigning to the contents (as with [:]) changes
the contents, but not the container variable, and as the container
element was passed in you'll see the changed item outside the function.
Emile
and assign to it the name 'list'." At this point, there is no longer
any name that refers to the object that the caller passed.
Here is I find on-line about "Arguments are passed by assignment."
http://stackoverflow.com/questions/986006/python-how-do-i-pass-a-variable-by-reference
"If you pass a mutable object into a method, the method gets a reference to that
same object and you can mutate it to your heart's delight, but if you rebind the
reference in the method, the outer scope will know nothing about it, and after
you're done, the outer reference will still point at the original object."
Thanks
--
https://mail.python.org/mailman/listinfo/python-list
