On Tuesday, July 22, 2014 3:04:09 PM UTC-4, fl wrote: Hi, Excuse me. I find that the OP misses some info. I rewrite it again:
I learn Python function call on tutorial. There is a link on this subject. http://robertheaton.com/2014/02/09/pythons-pass-by-object-reference-as-explained-by-philip-k-dick/ Although it explains clearly, the figure makes me puzzled. ""Python is different. As we know, in Python, "Object references are passed by value". A function receives a reference to (and will access) the same object in memory as used by the caller. However, it does not receive the box that the caller is storing this object in; as in pass-by-value, the function provides its own box and creates a new variable for itself. Let's try appending again:"" On the figure, I understand the figure about append function. Here is the lines: When I enter the command lines on my computer: >>> def append(list): ... list.append(1) ... >>> list=[0] >>> append(list) >>> print(list) [0, 1] But I don't understand the reassign function result: >>> def reassign(list): ... list=[0,1] ... >>> list=[0] >>> reassign(list) >>> print list [0] Questions: 1. From the tutorial explanation, both function append and reassign use pass-by-object-reference. Is it right? 2. The tutorial says: "The caller doesn't care if you reassign the function's box. Different boxes, same content." about the reassign function. I don't understand "Different boxes, same content". It uses different boxes (I agree). But the results are different for the caller ([0]) and the function reassign ([0, 1]). What is wrong with my understanding? Thanks a lot, -- https://mail.python.org/mailman/listinfo/python-list
