On 3/04/2014 11:50 PM, Marco Buttu wrote:
I prefere this one:bar = ['a','b','c','x','y','z'] v1, _, _, v2, v3, _ = bar I also like the solution with itemgetter: v1, v2, v3 = itemgetter(0, 3, 4)(bar) but I think it is less readable than the previous one
What if you wanted the 2nd, 37th, and 1007th items from a list?Personally, I find the 2nd form far more readable, once I got past my initial surprise that it would access a list of items.
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