On 04/02/2014 01:17 AM, Mark Lawrence wrote:
Came across this http://stackoverflow.com/questions/22756632/compact-way-to-assign-values-by-slicing-list-in-python?newsletter=1&nlcode=245176|202f - just curious what you guys and gals thought of the answers.
I prefere this one: bar = ['a','b','c','x','y','z'] v1, _, _, v2, v3, _ = bar I also like the solution with itemgetter: v1, v2, v3 = itemgetter(0, 3, 4)(bar) but I think it is less readable than the previous one -- Marco Buttu -- https://mail.python.org/mailman/listinfo/python-list
