You would be assuming a quantum leap type theory, that the object has no Vo->V1, it just adjusts to the constant immediately, instead of what I would call the quantum leap,without other 'theories' involved, that it has a classical physics type movement in which it can accelerate from a resting position, to a velocity, and then regain orbit:
http://wiki.answers.com/Q/What_is_a_quantum_leap On Tue, Apr 1, 2014 at 3:21 AM, David Hutto <dwightdhu...@gmail.com> wrote: > u is the initial velocity from a starting/resting point, not a static > speed at that point, and begins to accelerate, > over a particular timeframe, in which it's momentum is not stopped by > friction on which the rails/environment it travels upon has, or the similar > properties the object might have during acceleration in relation to the > environment it travels within. > > So the object has a starting point at which there is no equal, or opposing > force, as it begins to accelerate from a resting position(Newton: an object > will remain in motion, until acted upon by an equal or opposite force, and > in this case the motion is propulsion of the object, or the newtons of > propulsion, until it is moving at the exact speed of the propulsion applied > to the object->Vo-V1, with 0 friction/viscosity during this timeframe). > > The difference in our opinions, seems to be that there is an initial > resting state, and not at an already accelerated motion that has reached > it's maximum capacity. > > > So there is a dynamic in my mind's eye, where the object is at a "resting" > point initially, and either the environment, or the object can maneuver > their own viscosity in relation to the other. > > > On Tue, Apr 1, 2014 at 2:39 AM, Ian Kelly <ian.g.ke...@gmail.com> wrote: > >> On Tue, Apr 1, 2014 at 12:24 AM, David Hutto <dwightdhu...@gmail.com> >> wrote: >> >> >> >> >> (1) v = u + at >> >> >> (2) s = 1/2(u + v)t >> >> >> (3) s = ut + 1/2(at^2) >> >> >> (4) v^2 = u^2 + 2as >> >> >> >> >> >> Only (1) and (3) are needed. >> >> > >> >> > Okay, what's u here? Heh. >> >> >> >> u is the initial velocity; v is the velocity after accelerating at a >> for >> >> time t. >> > >> > >> > This assumes that the viscosity is in a state of superfluidity, and in a >> > perfect state between itself, and it's traveling environment. >> >> I fail to see how this is relevant. I would assume that the amount of >> friction is already modeled in the acceleration constants; if it were >> zero then the brakes would be nonfunctional and the train would not be >> able to accelerate or decelerate at all. In any case, a change in >> friction simply works out to a change in acceleration. The equations >> above still hold true. >> -- >> https://mail.python.org/mailman/listinfo/python-list >> > > > > -- > Best Regards, > David Hutto > *CEO:* *http://www.hitwebdevelopment.com > <http://www.hitwebdevelopment.com>* > -- Best Regards, David Hutto *CEO:* *http://www.hitwebdevelopment.com <http://www.hitwebdevelopment.com>*
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