On Thursday, March 20, 2014 11:58:43 PM UTC-4, Steven D'Aprano wrote: > On Thu, 20 Mar 2014 20:23:49 -0700, dtran.ru wrote: > > > > > Thanks for your input Dave. Would the line be: > > > > > > return numtochar(c1 + c2 %26) > > > > Yes, that's the line that Dave is talking about. > > > > The critical part is that expression "c1 + c2 %26" which gets calculated > > before being passed on to numtochar. The % operator is a form of division > > (it returns the remainder after division, so 12%5 returns 2) and like the > > regular division operator / and multiplication * it has higher precedence > > than addition. > > > > That means that "30 + 40 % 26" calculates the % part first: > > > > 30 + 40 % 26 > > => 30 + 14 > > => 54 > > > > What you probably want is to calculate the % last, not first. That means > > you need to perform the addition first. Use round brackets (parentheses) > > for that: > > > > (30 + 40) % 26 > > => 70 % 26 > > => 18 > > > > > > Does that help? > > > > > > > > > > -- > > Steven D'Aprano > > http://import-that.dreamwidth.org/
Ooh I understand now! I've been coding for hours and exhaustion has gotten to my head. Many thanks all of you as I now know the source of my folly. -- https://mail.python.org/mailman/listinfo/python-list
