On Thu, 20 Mar 2014 20:23:49 -0700, dtran.ru wrote: > Thanks for your input Dave. Would the line be: > > return numtochar(c1 + c2 %26)
Yes, that's the line that Dave is talking about. The critical part is that expression "c1 + c2 %26" which gets calculated before being passed on to numtochar. The % operator is a form of division (it returns the remainder after division, so 12%5 returns 2) and like the regular division operator / and multiplication * it has higher precedence than addition. That means that "30 + 40 % 26" calculates the % part first: 30 + 40 % 26 => 30 + 14 => 54 What you probably want is to calculate the % last, not first. That means you need to perform the addition first. Use round brackets (parentheses) for that: (30 + 40) % 26 => 70 % 26 => 18 Does that help? -- Steven D'Aprano http://import-that.dreamwidth.org/ -- https://mail.python.org/mailman/listinfo/python-list
