On Sat, Feb 15, 2014 at 8:43 AM, Marko Rauhamaa <ma...@pacujo.net> wrote: > Unfortunately neither the "everything is a reference" model nor the > "small/big" model help you predict the value of an "is" operator in the > ambiguous cases.
Can you give an example of an ambiguous case? Fundamentally, the 'is' operator tells you whether its two operands are exactly the same object, nothing more and nothing less, so I assume your "ambiguous cases" are ones where it's possible for two things to be either the same object or two indistinguishable ones. The only situation I can think of is that immutables are allowed to be interned, which is why this comes up True (in CPython) when it would come up False with larger values (as I demonstrated earlier): >>> x = 1 >>> y = 2 >>> z = x + y >>> z is 3 True ChrisA -- https://mail.python.org/mailman/listinfo/python-list
