On 15/11/2013 23:36, JL wrote:
Thanks! This is the answer which I am seeking. However, I am not able to get
the following line to work. I am using python 2.7.5
debug_print = print
Can we assign a function into a variable in this manner?
On Friday, November 15, 2013 11:49:52 AM UTC+8, Chris Angelico wrote:
On Fri, Nov 15, 2013 at 1:29 PM, JL <lightai...@gmail.com> wrote:
One of my favorite tools in C/C++ language is the preprocessor macros.
One example is switching certain print messages for debugging use only
#ifdef DEBUG_ENABLE
DEBUG_PRINT print
#else
DEBUG_PRINT
Is it possible to implement something similar in python? Thank you.
There are usually other ways to do things. For instance, you can
define a function to either do something or do nothing:
if debug_mode:
debug_print = print
else:
debug_print = lambda: None
debug_print("This won't be shown unless we're in debug mode!")
But as Dave says, you could write a preprocessor if you need one.
ChrisA
Yes but please don't top post. Actually print is a statement in Python
2 so your code should work if you use
from __future__ import print_function
at the top of your code.
Would you also be kind enough to read and action this
https://wiki.python.org/moin/GoogleGroupsPython to prevent the double
line spacing shown above, thanks.
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