Thanks! This is the answer which I am seeking. However, I am not able to get
the following line to work. I am using python 2.7.5
debug_print = print
Can we assign a function into a variable in this manner?
On Friday, November 15, 2013 11:49:52 AM UTC+8, Chris Angelico wrote:
> On Fri, Nov 15, 2013 at 1:29 PM, JL <lightai...@gmail.com> wrote:
>
> > One of my favorite tools in C/C++ language is the preprocessor macros.
>
> >
>
> > One example is switching certain print messages for debugging use only
>
> >
>
> > #ifdef DEBUG_ENABLE
>
> > DEBUG_PRINT print
>
> > #else
>
> > DEBUG_PRINT
>
> >
>
> > Is it possible to implement something similar in python? Thank you.
>
>
>
> There are usually other ways to do things. For instance, you can
>
> define a function to either do something or do nothing:
>
>
>
> if debug_mode:
>
> debug_print = print
>
> else:
>
> debug_print = lambda: None
>
>
>
> debug_print("This won't be shown unless we're in debug mode!")
>
>
>
> But as Dave says, you could write a preprocessor if you need one.
>
>
>
> ChrisA
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