On 22 Aug 2013 08:58, "chandan kumar" <chandan_...@yahoo.co.in> wrote: > > Hi all, > > Sorry for not explaining question properly.Here Its not about threading and dont worry about any indentations.Please see below example > > class Call_Constructor(): > def __init__(self): > print "In __init__ " > > class Test_Constructor(Call_Constructor): > def method(self): > print " In Test_Constructor Class" > > ConstructInstance = Test_Constructor() > > When an instace is created for Test_Constructor class ,The code flows starts __init__ in Call_Constructor class.Whys is it like that. > > > class Call_Constructor(): > def __init__(self): > print "In __init__ " > > > class Test_Constructor(Call_Constructor): > def __init__(self): > print " In Test_Constructor Class" > > ConstructInstance = Test_Constructor() > > But for the above case Code flows starts from Test_Constructor(). > > Whats is the difference for both cases described above. > > Best Regards, > Chandan.
When creating an instance, Python will call __init__. In the first example there was only an __init__ method in the base class, so that one was used. On the second example, there were __init__ methods on both classes, but since you instantiated the subclass, the subclass's __init__ method was executed. Subclass methods have precedence over base class methods. If you want the __init__ method of the base class in the second example to be called, you can either remove the subclass __init__ method or call super(TestConstructor, self).__init__() in that method. That will call the base class's __init__.
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