________________________________ > From: alyssonbr...@gmail.com > Date: Tue, 21 May 2013 09:03:13 -0300 > Subject: Re: PEP 378: Format Specifier for Thousands Separator > To: python-list@python.org > > This work in 3.1+: > > $ python3 > Python 3.1.3 (r313:86834, Nov 28 2010, 11:28:10) > [GCC 4.4.5] on linux2 > Type "help", "copyright", "credits" or "license" for more information. > >>> one_number = 1234567 > >>> print('number={:,}'.format(one_number)) > number=1,234,567 > >>> >
Thank you, but let me rephrase it. I'm already using str.format() but I'd like to use '%' (BINARY_MODULO) operator instead. I've looked into the source code of CPython 2.7.5 and I've found no evidence of the thousands separator been implemented on formatint() in "Objects/unicodeobject.c". I also didn't find the _PyString_FormatLong() used in formatlong(). Where is _PyString_FormatLong() located? So, the question is: Where would I change the CPython 2.7.5 source code to enable '%' (BINARY_MODULO) to format using the thousands separator like str.format() does, such as: >>>sys.stderr.write('%,d\n' % 1234567) 1,234,567 -- http://mail.python.org/mailman/listinfo/python-list