El martes, 7 de mayo de 2013 23:53:32 UTC+2, Terry Jan Reedy escribió:
> On 5/7/2013 4:27 PM, cheirasa...@gmail.com wrote:
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> > file = filedialog.askopenfile ( mode....... )
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> askopenfile is a convenience function that creates an Open dialog
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> object, shows it, gets the name returned by the dialog, opens the file
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> with that name, and returns an appropriate normal file object
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> > to open a file with an open dialog box, OK. Made it.
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> >
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> > How i get the name of the opened file?
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> file.name, (at least in 3.3), which in your example below is "file.doc"
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> > print(file)
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> >
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> > the output is: <......name="file.doc"...mode=......encoding.......... >
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> This is the standard string representation of a file object. It is
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> created from the various attributes of the file instance, including
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> file.name.
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> > How can i get the second member of 'file'?
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> Strings do not have fields. The second 'member', would be the second
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> character, file[1], which is not what you want.
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> > And i am unable to find a detailed reference to this object in the i.net
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> Use the Fine Manual. The entry for builtin open() function, which you
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> should read to understand the 'open' part of askopenfile, directs you to
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> the Glossary entry 'file object' which says "There are actually three
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> categories of file objects: raw binary files, buffered binary files and
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> text files. Their interfaces are defined in the io module. The canonical
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> way to create a file object is by using the open() function." The kind
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> of file object you get is determined by the mode ('b' present or not),
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> buffer arg, and maybe something else. You can look in the io chapter or
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> use dir() and help() as John G. suggested.
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> Python programmers should really learn to use dir(), help(), and the
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> manuls, including the index and module index.
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> --
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> Terry Jan Reedy
Yeah. This is an answer. A lot of thanks.
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