Well. It's driving me crazy. So simple.... I use:
file = filedialog.askopenfile ( mode....... ) to open a file with an open dialog box, OK. Made it. How i get the name of the opened file? i do : print(file) the output is: <......name="file.doc"...mode=......encoding.......... > How can i get the second member of 'file'? I had prove with print(file[1]) and print(file(1)) but does not work. And i am unable to find a detailed reference to this object in the i.net http://fossies.org/dox/Python-3.3.1/filedialog_8py_source.html#l00393 is where i could reach! Thanks -- http://mail.python.org/mailman/listinfo/python-list
