On 2/5/2013 1:38 PM, maiden129 wrote:
Hi,
I'm trying to create this program that counts the occurrences
> of each digit in a string which the user have to enter.
Here is my code:
s=input("Enter a string, eg(4856w23874): ")
s=list(s)
Unnecessary conversion.
checkS=['0','1','2','3','4','5','6','7','8','9']
checks = '0123456789' is much easier to type.
for i in s:
if i in checkS:
Loop through checks, not s
t=s.count(i)
if t>1:
for k in range(1,t):
s=s.remove(i)
print(i, "occurs", t,"times.")
elif t==1:
print(i,"occurs 1 time.")
else: pass
Replace everything with
s = input("Enter a string of digits: ")
for d in '0123456789':
c = s.count(d)
if c:
print("{} occurs {} time{}".format(d, c, '' if c == 1 else 's'))
Enter a string of digits: 12233344499
1 occurs 1 time
2 occurs 2 times
3 occurs 3 times
4 occurs 3 times
9 occurs 2 times
--
Terry Jan Reedy
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