Hi Sia,
Find a multi-digit method in this version:
from string import maketrans
from itertools import takewhile
def is_digit(s): return s.isdigit()
class redux:
def __init__(self):
intab = '+-'
outtab = ' '
self.trantab = maketrans(intab, outtab)
def reduce_plusminus(self, s):
list_form = [r[int(r[0]) + 1:] if r[0].isdigit() else r
for r
in s.translate(self.trantab).split()]
return ''.join(list_form)
def reduce_plusminus_multi_digit(self, s):
spl = s.translate(self.trantab).split()
digits = [list(takewhile(is_digit, r))
for r
in spl]
numbers = [int(''.join(r)) if r else 0
for r
in digits]
skips = [len(dig) + num for dig, num in zip(digits, numbers)]
return ''.join([s[r:] for r, s in zip(skips, spl)])
if __name__ == "__main__":
p = redux()
print p.reduce_plusminus(".+3ACG.+5CAACG.+3ACG.+3ACG")
print p.reduce_plusminus("tA.-2AG.-2AG,-2ag")
print 'multi-digit...'
print p.reduce_plusminus_multi_digit(".+3ACG.+5CAACG.+3ACG.+3ACG")
print p.reduce_plusminus_multi_digit(".+12ACGACGACGACG.+5CAACG.+3ACG.+3ACG")
HTH,
Nick
On Saturday, 5 January 2013 19:35:26 UTC+11, Sia wrote:
> I have strings such as:
>
>
>
> tA.-2AG.-2AG,-2ag
>
> or
>
> .+3ACG.+5CAACG.+3ACG.+3ACG
>
>
>
> The plus and minus signs are always followed by a number (say, i). I want
> python to find each single plus or minus, remove the sign, the number after
> it and remove i characters after that. So the two strings above become:
>
>
>
> tA..,
>
> and
>
> ...
>
>
>
> How can I do that?
>
> Thanks.
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