Hi Sia,
Here's another variation. It's within my tolerance for readability :-) and also
quick, if that's an issue. It does 100,000 of your longer string in a couple of
seconds on my venerable laptop.
It handles only single-digit numbers. For multi-digit, I'd be inclined to have
a look at takewhile and/or dropwhile, both in itertools (Python 2.7 and 3.x
only.)
from string import maketrans
class redux:
def __init__(self):
intab = '+-'
outtab = ' ' # two spaces
self.trantab = maketrans(intab, outtab)
def reduce_plusminus(self, s):
list_form = [r[int(r[0]) + 1:] if r[0].isdigit() else r
for r
in s.translate(self.trantab).split()]
return ''.join(list_form)
if __name__ == "__main__":
p = redux()
print p.reduce_plusminus(".+3ACG.+5CAACG.+3ACG.+3ACG")
print p.reduce_plusminus("tA.-2AG.-2AG,-2ag")
for n in range(100000): p.reduce_plusminus(".+3ACG.+5CAACG.+3ACG.+3ACG")
On Saturday, 5 January 2013 19:35:26 UTC+11, Sia wrote:
> I have strings such as:
>
>
>
> tA.-2AG.-2AG,-2ag
>
> or
>
> .+3ACG.+5CAACG.+3ACG.+3ACG
>
>
>
> The plus and minus signs are always followed by a number (say, i). I want
> python to find each single plus or minus, remove the sign, the number after
> it and remove i characters after that. So the two strings above become:
>
>
>
> tA..,
>
> and
>
> ...
>
>
>
> How can I do that?
>
> Thanks.
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