Hello rusi
This is a little bit faster:
s = "apple"
[s[i:i+2] for i in range(len(s)-1)]
>>> timeit("""s = "apple"
... [a+b for a,b in zip(s, s[1:])]""",number=10000)
0.061038970947265625
>>> timeit("""s = "apple"
... [s[i:i+2] for i in range(len(s)-1)]""",number=10000)
0.0467379093170166
Regards
From: rusi <rustompm...@gmail.com>
Date: 22 October 2012 17:19:35 IST
To: python-list@python.org
Subject: Re: get each pair from a string.
On 10/21/2012 11:33 AM, Vincent Davis wrote:
I am looking for a good way to get every pair from a string. For
example,
input:
x = 'apple'
output
'ap'
'pp'
'pl'
'le'
Maybe zip before izip for a noob?
s="apple"
[a+b for a,b in zip(s, s[1:])]
['ap', 'pp', 'pl', 'le']
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