On 12/08/12 22:13:20, Alister wrote: > On Sun, 12 Aug 2012 19:20:26 +0100, Mark Lawrence wrote: > >> On 12/08/2012 17:59, Paul Rubin wrote: >>>> which can be simplified to: >>>> for x in range(len(L)//2 + len(L)%2): >>> >>> for x in range(sum(divmod(len(L), 2))): ... >>> >>> >> So who's going to be first in with "and thou shalt not count to 4..."? > > Five is right out
Neither count thou two, excepting that thou then proceed to three -- HansM -- http://mail.python.org/mailman/listinfo/python-list
