On Sat, 11 Aug 2012 17:54:40 -0700, Paul Rubin wrote:
> John Ladasky <john_lada...@sbcglobal.net> writes:
[...]
>> If the length of the list L is odd, I want to process it once. If
>> len(L) is even, I want to process it twice....
>> for x in range(1 + not(len(L) % 2)):
>
> If you really have to do something like that, I'd say
>
> for x in range(1 + (len(L) & 1)):
[snip]
I'd simplify it even more:
for x in (0,) if len(L)%2 else (0, 1):
...
which is even more explicit and simpler to read even though it is longer.
--
Steven
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