On 19/05/2012 02:59, Steven D'Aprano wrote:
I have matplotlib and iPython, and want to plot a function over an equally-spaced range of points.That is to say, I want to say something like this: plot(func, start, end) rather than generating the X and Y values by hand, and plotting a scatter graph. All the examples I've seen look something like this: from pylab import * import numpy as np t = arange(0.0, 2.0+0.01, 0.01) # generate x-values s = sin(t*pi) # and y-values plot(t, s) show() which is fine for what it is, but I'm looking for an interface closer to what my HP graphing calculator would use, i.e. something like this: plot(lambda x: sin(x*pi), # function or expression to plot, start=0.0, end=2.0, ) and have step size taken either from some default, or better still, automatically calculated so one point is calculated per pixel. Is there a way to do this in iPython or matplotlib?
Sorry don't know but wouldn't it make sense to ask on the matplotlib users mailing lst, cos like most python users the're extremely friendly?
-- Cheers. Mark Lawrence. -- http://mail.python.org/mailman/listinfo/python-list
