Hi Is this possible at all?
Cheers Adam On Mon, Jan 23, 2012 at 14:01, Adam Mercer <ramer...@gmail.com> wrote: > Hi > > I'm trying to write a script that determines the version of OpenSSL > that python is linked against, using python-2.7 this is easy as I can > use: > > import ssl > ssl.OPENSSL_VERSION > > but unfortunately I need to support python-2.6, from an older script I > used the following: > > import _ssl > ssl_lib = _ssl.__file__ > > to get the path to the _ssl.so module and then I parsed the output of > ldd (on linux) to get the path to the OpenSSL library and then parsed > the version from the filename. In other words it's very messy. > > I had a little success using this approach but I have recently > received a bug report that this doesn't seem to work on Debian > Squeeze. When I try to query the __file__ attribute of the _ssl module > I get the following error: > >>>> import _ssl >>>> _ssl.__file__ > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > AttributeError: 'module' object has no attribute '__file__' >>>> > > Can anyone offer any suggestions as to what is going wrong with the > above code or offer an alternative way of determining the OpenSSl > version using python-2.6? > > Cheers > > Adam -- http://mail.python.org/mailman/listinfo/python-list
