Hi
I'm trying to write a script that determines the version of OpenSSL
that python is linked against, using python-2.7 this is easy as I can
use:
import ssl
ssl.OPENSSL_VERSION
but unfortunately I need to support python-2.6, from an older script I
used the following:
import _ssl
ssl_lib = _ssl.__file__
to get the path to the _ssl.so module and then I parsed the output of
ldd (on linux) to get the path to the OpenSSL library and then parsed
the version from the filename. In other words it's very messy.
I had a little success using this approach but I have recently
received a bug report that this doesn't seem to work on Debian
Squeeze. When I try to query the __file__ attribute of the _ssl module
I get the following error:
>>> import _ssl
>>> _ssl.__file__
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'module' object has no attribute '__file__'
>>>
Can anyone offer any suggestions as to what is going wrong with the
above code or offer an alternative way of determining the OpenSSl
version using python-2.6?
Cheers
Adam
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